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Question-173499




Question Number 173499 by cortano1 last updated on 12/Jul/22
Commented by blackmamba last updated on 12/Jul/22
 x=1+r    L = lim_(r→0)  ((((7+(1+r)^3 ))^(1/3) −(√(3+(1+r)^2 )))/r)       = lim_(r→0)  ((((8+(3r+3r^2 +r^3 )))^(1/3) −(√(4+(2r+r^2 ))))/r)      = lim_(r→0)  ((2 ((1+(((3r+3r^2 +r^3 )/8))))^(1/3) −2(√(1+(((2r+r^2 )/4)))))/r)      = lim_(r→0)  ((2(1+((3r+3r^2 +r^3 )/(24)))−2(1+(((2r+r^2 )/8))))/r)    = lim_(r→0)  ((3+3r+r^2 )/(12)) −((2+r)/4)    = −(1/4)
x=1+rL=limr07+(1+r)333+(1+r)2r=limr08+(3r+3r2+r3)34+(2r+r2)r=limr021+(3r+3r2+r38)321+(2r+r24)r=limr02(1+3r+3r2+r324)2(1+(2r+r28))r=limr03+3r+r2122+r4=14
Commented by Tawa11 last updated on 13/Jul/22
Great sir
Greatsir

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