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Question-173652




Question Number 173652 by saly last updated on 15/Jul/22
Commented by saly last updated on 15/Jul/22
  Help me
Helpme
Commented by JDamian last updated on 15/Jul/22
you really need help −have you missed any term?
youreallyneedhelphaveyoumissedanyterm?
Commented by saly last updated on 15/Jul/22
    log(√((2022)/(x^3 +x+2)))
log2022x3+x+2
Answered by okbruh123 last updated on 15/Jul/22
first of all, theres no base mentioned.  so i am assuming its common log  since base > 0 and ≠1, we need not worry about it.  ⇒(√(((2022)/(x^3 +x+2)) )) > 0 ∩ x^3 +x+2≠0  ⇒ as square root is always ≥ 0 and in this case also ≠ 0  ⇒ x ∈ R ∩ (x+1)+x^3 +1 ≠ 0  ⇒ x ∈ R ∩ (x+1)+(x+1)(x^2 +1−x)≠0  ⇒ R ∩ (x+1)(x^2 −x+2) ≠0⇒x≠−1   ⇒ x ∈ R−{−1}  this was domain.  ill answer range separately
firstofall,theresnobasementioned.soiamassumingitscommonlogsincebase>0and1,weneednotworryaboutit.2022x3+x+2>0x3+x+20assquarerootisalways0andinthiscasealso0xR(x+1)+x3+10xR(x+1)+(x+1)(x2+1x)0R(x+1)(x2x+2)0x1xR{1}thiswasdomain.illanswerrangeseparately

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