Menu Close

Question-173807




Question Number 173807 by mokys last updated on 18/Jul/22
Answered by aleks041103 last updated on 18/Jul/22
h(t)=∫_0 ^( t) f(x)g(t−x)dx  h is the convolution of f and g.  for convolution and the laplace transform  it′s true that:  L[h]=L[f]L[g]  ⇒L[h]=((s+2)/(s^2 +1)) ((s^2 +1)/((s+3)(s+2)))  ⇒L[h](s)=(1/(s+3))
h(t)=t0f(x)g(tx)dxhistheconvolutionoffandg.forconvolutionandthelaplacetransformitstruethat:L[h]=L[f]L[g]L[h]=s+2s2+1s2+1(s+3)(s+2)L[h](s)=1s+3

Leave a Reply

Your email address will not be published. Required fields are marked *