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Question-174719




Question Number 174719 by AgniMath last updated on 09/Aug/22
Answered by behi834171 last updated on 09/Aug/22
a+b≠0  ⇒((a+b)/(ab))=(1/(a+b))⇒(a+b)^2 =ab⇒  ⇒a^2 +ab+b^2 =0⇒^(a≠b) (a−b)(a^2 +ab+b^2 )=0  ⇒a^3 −b^3 =0⇒a^3 =b^3     .■
$$\boldsymbol{{a}}+\boldsymbol{{b}}\neq\mathrm{0} \\ $$$$\Rightarrow\frac{\boldsymbol{{a}}+\boldsymbol{{b}}}{\boldsymbol{{ab}}}=\frac{\mathrm{1}}{\boldsymbol{{a}}+\boldsymbol{{b}}}\Rightarrow\left(\boldsymbol{{a}}+\boldsymbol{{b}}\right)^{\mathrm{2}} =\boldsymbol{{ab}}\Rightarrow \\ $$$$\Rightarrow\boldsymbol{{a}}^{\mathrm{2}} +\boldsymbol{{ab}}+\boldsymbol{{b}}^{\mathrm{2}} =\mathrm{0}\overset{\boldsymbol{{a}}\neq\boldsymbol{{b}}} {\Rightarrow}\left(\boldsymbol{{a}}−\boldsymbol{{b}}\right)\left(\boldsymbol{{a}}^{\mathrm{2}} +\boldsymbol{{ab}}+\boldsymbol{{b}}^{\mathrm{2}} \right)=\mathrm{0} \\ $$$$\Rightarrow\boldsymbol{{a}}^{\mathrm{3}} −\boldsymbol{{b}}^{\mathrm{3}} =\mathrm{0}\Rightarrow\boldsymbol{{a}}^{\mathrm{3}} =\boldsymbol{{b}}^{\mathrm{3}} \:\:\:\:.\blacksquare \\ $$

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