Question Number 174767 by Best1 last updated on 10/Aug/22
Answered by Ar Brandon last updated on 10/Aug/22
$$\mathrm{60}+\frac{\mathrm{1}}{\mathrm{3}}\left(\mathrm{60}+\mathrm{60}\right)+\frac{\mathrm{1}}{\mathrm{9}}\left(\mathrm{60}+\mathrm{60}\right)+\frac{\mathrm{1}}{\mathrm{27}}\left(\mathrm{60}+\mathrm{60}\right)+\frac{\mathrm{1}}{\mathrm{81}}\left(\mathrm{60}+\mathrm{60}\right) \\ $$$$=\mathrm{60}+\frac{\mathrm{120}}{\mathrm{3}}+\frac{\mathrm{120}}{\mathrm{9}}+\frac{\mathrm{120}}{\mathrm{27}}+\frac{\mathrm{120}}{\mathrm{81}} \\ $$$$=\mathrm{119}.\mathrm{2592593}\:\mathrm{m} \\ $$