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Question-174859




Question Number 174859 by Shrinava last updated on 12/Aug/22
Commented by Frix last updated on 12/Aug/22
(a/b)=k ⇔ a=bk etc. ⇒ a+2c+3e=(b+2d+3f)k  answer is k
$$\frac{{a}}{{b}}={k}\:\Leftrightarrow\:{a}={bk}\:\mathrm{etc}.\:\Rightarrow\:{a}+\mathrm{2}{c}+\mathrm{3}{e}=\left({b}+\mathrm{2}{d}+\mathrm{3}{f}\right){k} \\ $$$$\mathrm{answer}\:\mathrm{is}\:{k} \\ $$
Answered by behi834171 last updated on 12/Aug/22
=  k  .■  (a/b)=(c/d)=((a+c)/(b+d))=((ma+nc)/(mb+nd))=......
$$=\:\:\boldsymbol{{k}}\:\:.\blacksquare \\ $$$$\frac{\boldsymbol{{a}}}{\boldsymbol{{b}}}=\frac{\boldsymbol{{c}}}{\boldsymbol{{d}}}=\frac{\boldsymbol{{a}}+\boldsymbol{{c}}}{\boldsymbol{{b}}+\boldsymbol{{d}}}=\frac{\boldsymbol{{ma}}+\boldsymbol{{nc}}}{\boldsymbol{{mb}}+\boldsymbol{{nd}}}=…… \\ $$

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