Menu Close

Question-174975




Question Number 174975 by sciencestudent last updated on 15/Aug/22
Answered by MikeH last updated on 15/Aug/22
R_1 +R_2  = 690 or x+y = 690.....(1)  ((xy)/(x+y)) = 150  ⇒ ((xy)/(690)) = 150 ⇒ xy = 103500   from (1) x = 690−y  ⇒ y(690−y)= 103500  ⇒ y^2 −690y +103500 =0  y = 220.4 Ω or y = 469.6 Ω  so R_1  = 220.4Ω and R_2  = 469.6Ω
R1+R2=690orx+y=690..(1)xyx+y=150xy690=150xy=103500from(1)x=690yy(690y)=103500y2690y+103500=0y=220.4Ωory=469.6ΩsoR1=220.4ΩandR2=469.6Ω

Leave a Reply

Your email address will not be published. Required fields are marked *