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Question-175434




Question Number 175434 by thean last updated on 30/Aug/22
Answered by Mathspace last updated on 30/Aug/22
=lim_(x→0^+ ) (((x^2 −2−2xlnx+3x)/x))  =lim_(x→0^+ )    ((x^2 +3x−2)/x)  =lim_(x→0+)    ((−2)/x)=−∞
$$={lim}_{{x}\rightarrow\mathrm{0}^{+} } \left(\frac{{x}^{\mathrm{2}} −\mathrm{2}−\mathrm{2}{xlnx}+\mathrm{3}{x}}{{x}}\right) \\ $$$$={lim}_{{x}\rightarrow\mathrm{0}^{+} } \:\:\:\frac{{x}^{\mathrm{2}} +\mathrm{3}{x}−\mathrm{2}}{{x}} \\ $$$$={lim}_{{x}\rightarrow\mathrm{0}+} \:\:\:\frac{−\mathrm{2}}{{x}}=−\infty \\ $$

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