Question Number 175894 by cortano1 last updated on 09/Sep/22
Answered by mr W last updated on 09/Sep/22
Commented by mr W last updated on 09/Sep/22
$${a}^{\mathrm{2}} =\mathrm{10}^{\mathrm{2}} +\left({a}−\mathrm{5}\right)^{\mathrm{2}} \\ $$$$\Rightarrow{a}=\mathrm{12}.\mathrm{5} \\ $$$$\left({a}+{R}\right)^{\mathrm{2}} ={a}^{\mathrm{2}} +\left(\mathrm{10}−{R}\right)^{\mathrm{2}} \\ $$$$\left(\mathrm{20}+\mathrm{2}{a}\right){R}=\mathrm{100} \\ $$$$\Rightarrow{R}=\frac{\mathrm{100}}{\mathrm{45}}=\frac{\mathrm{20}}{\mathrm{9}}\:\checkmark \\ $$
Commented by cortano1 last updated on 10/Sep/22
$$\mathrm{nice} \\ $$
Commented by Tawa11 last updated on 15/Sep/22
$$\mathrm{Great}\:\mathrm{sir} \\ $$