Question Number 176206 by mathlove last updated on 15/Sep/22
Answered by TheHoneyCat last updated on 18/Sep/22
$$\mathrm{a}=\mathrm{1}\:\Rightarrow \\ $$$$\mathrm{1}^{\mathrm{1}} .\left(\left(\mathrm{2}^{\mathrm{1}} \right)^{\mathrm{1}} \right)^{\mathrm{2}} =\mathrm{1}.\left(\mathrm{2}^{\mathrm{1}} \right)^{\mathrm{2}} =\mathrm{2}^{\mathrm{2}} =\mathrm{4}\:\:_{\Box} \\ $$
Commented by mathlove last updated on 19/Sep/22
$${no} \\ $$$${a}^{{a}^{{a}} } \neq\left(\left({a}\right)^{{a}} \right)^{{a}} \\ $$