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Question-176303

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Question Number 176303 by infinityaction last updated on 16/Sep/22
Answered by cortano1 last updated on 16/Sep/22
let { ((a+b=x)),((c+d=y)) :}⇒x+y=2 ; y=2−x M=f(x)= x(2−x)=2x−x^2 ; x≥0 ⇒0≤f(x)≤1 ⇒0≤ M≤1
let{a+b=xc+d=y⇒x+y=2;y=2−xM=f(x)=x(2−x)=2x−x2;x⩾0⇒0⩽f(x)⩽1⇒0⩽M⩽1
Commented by cortano1 last updated on 16/Sep/22
yes..sir. thanks
yes..sir.thanks

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