Question Number 176673 by cortano1 last updated on 24/Sep/22
Answered by mr W last updated on 24/Sep/22
$$=\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\frac{\mathrm{14}\left({x}^{\mathrm{6}} −\mathrm{1}\right)^{\frac{\mathrm{6}}{\mathrm{7}}} }{\mathrm{15}{x}^{\frac{\mathrm{26}}{\mathrm{5}}} }=\mathrm{0} \\ $$