Question Number 176821 by Ar Brandon last updated on 27/Sep/22
Commented by som(math1967) last updated on 27/Sep/22
$$\:\frac{{AF}}{{AL}}=\frac{\frac{{BC}}{\mathrm{2}}+{CE}+\frac{{EK}}{\mathrm{2}}}{\frac{{BC}}{\mathrm{2}}+{CE}+{EK}+\frac{{KM}}{\mathrm{2}}} \\ $$$$\:\:=\frac{.\mathrm{5}+\mathrm{2}+\mathrm{2}}{.\mathrm{5}+\mathrm{2}+\mathrm{4}+\mathrm{8}}=\frac{\mathrm{4}.\mathrm{5}}{\mathrm{14}.\mathrm{5}}=\frac{\mathrm{9}}{\mathrm{29}} \\ $$
Commented by Ar Brandon last updated on 27/Sep/22
Thank you Sir