Question-176925

Question Number 176925 by Ar Brandon last updated on 28/Sep/22

Answered by mindispower last updated on 28/Sep/22

$$={x}^{\mathrm{2}} +{y}^{\mathrm{2}} −\mathrm{2}{xy}+{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{4} \\ $$$$\left({x}−{y}\right)^{\mathrm{2}} +\left({x}−\mathrm{2}\right)^{\mathrm{2}} =\mathrm{0} \\ $$$${x}={y}=\mathrm{2} \\ $$

Commented by Ar Brandon last updated on 28/Sep/22

Thanks, Sir! I stopped on the second line.

Commented by mindispower last updated on 28/Sep/22

$${avec}\:{plaisir}\:{bonne}\:{journee} \\ $$

Commented by Ar Brandon last updated on 28/Sep/22

Merci monsieur ! Meilleure à vous✨

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