Question Number 176936 by Ar Brandon last updated on 28/Sep/22
Answered by mr W last updated on 28/Sep/22
$$\frac{{x}}{\mathrm{sin}\:\left(\mathrm{15}+\mathrm{30}\right)}=\frac{\mathrm{4}\left(\sqrt{\mathrm{3}}−\mathrm{1}\right)}{\mathrm{sin}\:\mathrm{15}} \\ $$$${x}=\frac{\mathrm{4}\left(\sqrt{\mathrm{3}}−\mathrm{1}\right)×\mathrm{4}}{\left(\sqrt{\mathrm{6}}−\sqrt{\mathrm{2}}\right)}×\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}=\mathrm{8}\:{cm}\:\checkmark \\ $$
Commented by Ar Brandon last updated on 28/Sep/22
$$\mathrm{Thanks}\:\mathrm{Sir}.\:\mathrm{Sine}\:\mathrm{rule}.\:\mathrm{I}\:\mathrm{remember}. \\ $$