Question Number 177013 by mr W last updated on 29/Sep/22
Commented by mr W last updated on 29/Sep/22
$${find}\:{the}\:{area}\:{of}\:{the}\:{sector}. \\ $$
Answered by Rasheed.Sindhi last updated on 29/Sep/22
$$\mathcal{T}{he}\:{diameter}=\sqrt{\mathrm{4}^{\mathrm{2}} +\left(\mathrm{3}+\mathrm{5}\right)^{\mathrm{2}} }\:=\mathrm{4}\sqrt{\mathrm{5}} \\ $$$${Rsdius}=\mathrm{2}\sqrt{\mathrm{5}} \\ $$$${Area}\:{of}\:{circle}=\pi\left(\mathrm{2}\sqrt{\mathrm{5}}\:\right)^{\mathrm{2}} =\mathrm{20}\pi \\ $$$${Area}\:{of}\:{sector}=\frac{\mathrm{20}\pi}{\mathrm{4}}=\mathrm{5}\pi \\ $$
Commented by mr W last updated on 29/Sep/22
Commented by Rasheed.Sindhi last updated on 29/Sep/22
Commented by mr W last updated on 29/Sep/22
Commented by Rasheed.Sindhi last updated on 29/Sep/22
$$\mathbb{T}\boldsymbol{\mathrm{han}}\Bbbk\boldsymbol{\mathrm{s}}\:\mathrm{for}\:\mathrm{diagram}\:\boldsymbol{\mathrm{sir}}! \\ $$🙏🌷🌹🙏
Commented by mr W last updated on 30/Sep/22
$${thanks}\:{for}\:{smart}\:{solution}\:{sir}! \\ $$
Commented by Tawa11 last updated on 02/Oct/22
$$\mathrm{Great}\:\mathrm{sirs} \\ $$