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Question-177560




Question Number 177560 by aurpeyz last updated on 07/Oct/22
Commented by aurpeyz last updated on 07/Oct/22
Thank you Sir
ThankyouSir
Answered by Rasheed.Sindhi last updated on 07/Oct/22
Let the big list contsins x data items  A contains (x/2) items  ∵ Average of A is 12  ∴ The total of A is 12×(x/2)=6x  B contains (x/5) items  ∵ Average of B is 15  ∴ The total of B is 15×(x/5)=3x  C contains x−((x/2)+(x/5))=((10x−5x−2x)/(10))=((3x)/(10))  ∵ Average of C is 6  ∴ The total of C is 6×((3x)/(10))=((9x)/5)  The total of big list is  6x+3x+((9x)/5)=((30x+15x+9x)/5)=((54x)/5)  The average of big list=(((54x)/5)/x)         =10.8
LetthebiglistcontsinsxdataitemsAcontainsx2itemsAverageofAis12ThetotalofAis12×x2=6xBcontainsx5itemsAverageofBis15ThetotalofBis15×x5=3xCcontainsx(x2+x5)=10x5x2x10=3x10AverageofCis6ThetotalofCis6×3x10=9x5Thetotalofbiglistis6x+3x+9x5=30x+15x+9x5=54x5Theaverageofbiglist=(54x)/5x=10.8
Commented by aurpeyz last updated on 07/Oct/22
thanks
thanks
Answered by Rasheed.Sindhi last updated on 07/Oct/22
Let grand list contains 10 data items  (A number divisible by 2 & 5)  A contains 5 items(Half of 10)  Total of A=average×number of items                         = 12×5=60  B contains 2 items(One-fifth of 10)  Total of B=15×2=30  C contains 10−(5+2)=3 items  Total of C=6×3=18 items  Total of grand list=60+30+18=108  Average of grand list=((108)/(10))=10.8
Letgrandlistcontains10dataitems(Anumberdivisibleby2&5)Acontains5items(Halfof10)TotalofA=average×numberofitems=12×5=60Bcontains2items(Onefifthof10)TotalofB=15×2=30Ccontains10(5+2)=3itemsTotalofC=6×3=18itemsTotalofgrandlist=60+30+18=108Averageofgrandlist=10810=10.8
Commented by aurpeyz last updated on 07/Oct/22
thanks
thanks

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