Question-178737

Question Number 178737 by cherokeesay last updated on 21/Oct/22

Answered by Rasheed.Sindhi last updated on 21/Oct/22

Commented by Rasheed.Sindhi last updated on 21/Oct/22

Let AC = BC = r

blue - area = \frac{1}{4} π r^{2}

R = \frac{AB}{2} = \frac{\sqrt{r^{2} + r^{2}}}{2} = \frac{\sqrt{2} r}{2}

outer circle = π R^{2} = π {(\frac{\sqrt{2} r}{2})}^{2}

yello - area = outer circle - blue - area

= π {(\frac{\sqrt{2} r}{2})}^{2} - \frac{1}{4} π r^{2} = \frac{2 π r^{2}}{4} - \frac{π r^{2}}{4} = \frac{π r^{2}}{4}

= blue - area

Commented by cherokeesay last updated on 21/Oct/22

G r e e t! t h a n k y o u

Commented by Tawa11 last updated on 21/Oct/22

Great sir

Answered by HeferH last updated on 21/Oct/22

B l u e a r e a :

\frac{π {(r \sqrt{2})}^{2}}{4} = \frac{π r^{2}}{2}

Y e l l o w a r e a :

π r^{2} - b l u e = \frac{π r^{2}}{2}

t h e n y e l l o w = b l u e

Commented by cherokeesay last updated on 21/Oct/22

N i c e! t h a n k y o u!

Commented by Tawa11 last updated on 21/Oct/22

Great sir

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