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Question-178746




Question Number 178746 by Acem last updated on 21/Oct/22
Answered by mr W last updated on 21/Oct/22
s=total length of chain=3L=3 m  ((2mg)/3)×(s/3)−((mg)/3)×(s/6)=((mv^2 )/2)  ⇒v=(√((gs)/3))=(√g) m/s
$${s}={total}\:{length}\:{of}\:{chain}=\mathrm{3}{L}=\mathrm{3}\:{m} \\ $$$$\frac{\mathrm{2}{mg}}{\mathrm{3}}×\frac{{s}}{\mathrm{3}}−\frac{{mg}}{\mathrm{3}}×\frac{{s}}{\mathrm{6}}=\frac{{mv}^{\mathrm{2}} }{\mathrm{2}} \\ $$$$\Rightarrow{v}=\sqrt{\frac{{gs}}{\mathrm{3}}}=\sqrt{{g}}\:{m}/{s} \\ $$
Commented by Tawa11 last updated on 21/Oct/22
Great sir
$$\mathrm{Great}\:\mathrm{sir} \\ $$
Commented by Acem last updated on 21/Oct/22
Morning friend, its length= 1m
$${Morning}\:{friend},\:{its}\:{length}=\:\mathrm{1}{m} \\ $$
Commented by mr W last updated on 21/Oct/22
that is not important. when you   understand that L=1m is the total  length, it′s ok. but i understand that  L=1 m is only one third of the total  length.
$${that}\:{is}\:{not}\:{important}.\:{when}\:{you}\: \\ $$$${understand}\:{that}\:{L}=\mathrm{1}{m}\:{is}\:{the}\:{total} \\ $$$${length},\:{it}'{s}\:{ok}.\:{but}\:{i}\:{understand}\:{that} \\ $$$${L}=\mathrm{1}\:{m}\:{is}\:{only}\:{one}\:{third}\:{of}\:{the}\:{total} \\ $$$${length}. \\ $$
Commented by Acem last updated on 21/Oct/22
Yes friend, i know that isn′t important, what′s   interested in is knowing how to deal with the C_(gr)    for the free section of that chain, thanks
$${Yes}\:{friend},\:{i}\:{know}\:{that}\:{isn}'{t}\:{important},\:{what}'{s} \\ $$$$\:{interested}\:{in}\:{is}\:{knowing}\:{how}\:{to}\:{deal}\:{with}\:{the}\:{C}_{{gr}} \\ $$$$\:{for}\:{the}\:{free}\:{section}\:{of}\:{that}\:{chain},\:{thanks} \\ $$

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