Question Number 178780 by Laftex234 last updated on 21/Oct/22
Answered by MJS_new last updated on 21/Oct/22
$$\mathrm{lhs}\:\mathrm{is}\:\mathrm{defined}\:\mathrm{for}\:−\mathrm{1}\leqslant{x}\leqslant\mathrm{1}\:\mathrm{and}\:\mathrm{the}\:\mathrm{maximum} \\ $$$$\mathrm{is}\:\frac{\mathrm{5}\pi^{\mathrm{2}} }{\mathrm{16}}\:\mathrm{at}\:{x}=\pm\mathrm{1}\:\Rightarrow\:\mathrm{no}\:\mathrm{solution} \\ $$
Answered by Spillover last updated on 21/Oct/22
$$\mathrm{x}=−\mathrm{1}\:? \\ $$