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Question-178780




Question Number 178780 by Laftex234 last updated on 21/Oct/22
Answered by MJS_new last updated on 21/Oct/22
lhs is defined for −1≤x≤1 and the maximum  is ((5π^2 )/(16)) at x=±1 ⇒ no solution
$$\mathrm{lhs}\:\mathrm{is}\:\mathrm{defined}\:\mathrm{for}\:−\mathrm{1}\leqslant{x}\leqslant\mathrm{1}\:\mathrm{and}\:\mathrm{the}\:\mathrm{maximum} \\ $$$$\mathrm{is}\:\frac{\mathrm{5}\pi^{\mathrm{2}} }{\mathrm{16}}\:\mathrm{at}\:{x}=\pm\mathrm{1}\:\Rightarrow\:\mathrm{no}\:\mathrm{solution} \\ $$
Answered by Spillover last updated on 21/Oct/22
x=−1 ?
$$\mathrm{x}=−\mathrm{1}\:? \\ $$

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