Question-179440

Question Number 179440 by mr W last updated on 29/Oct/22

Commented by mr W last updated on 29/Oct/22

f i n d t h e l a r g e s t e q u i l a t e r a l t r i a n g l e

w h i c h c a n b e p l a c e d i n s i d e a s q u a r e

w i t h s i d e l e n g t h 1 .

Commented by Beginner last updated on 29/Oct/22

A p p r o x 1.0353

Commented by nikif99 last updated on 29/Oct/22

x^{2} = a^{2} + 1^{2} = b^{2} + 1^{2} \Rightarrow a = b \Rightarrow ϑ = 15 ° \Rightarrow

a = (\tan 15) / 1 = 2 - \sqrt{3}

x = \sqrt{{(2 - \sqrt{3})}^{2} + 1} = 2 \sqrt{2 - \sqrt{3}} = 1.0353 a p p r o x .

Commented by nikif99 last updated on 29/Oct/22

Commented by mr W last updated on 29/Oct/22

t h a n k s s i r s!

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