Question-179631

Question Number 179631 by daus last updated on 31/Oct/22

Commented by daus last updated on 31/Oct/22

s o l v e f o r x

Answered by Rasheed.Sindhi last updated on 31/Oct/22

64^{4 x} = {(\frac{1}{4})}^{3 x}

4^{12 x} . 4^{3 x} = 1

4^{15 x} = 4^{0}

15 x = 0

x = 0

Commented by daus last updated on 31/Oct/22

t h a n k s

Answered by Acem last updated on 01/Nov/22

64^{4 x} = 0 . 25^{3 x}

12 x \ln 4 = - 3 x \ln 4

15 x \ln 4 = 0 \Rightarrow x = 0

Answered by Rasheed.Sindhi last updated on 01/Nov/22

64^{4 x} = {(\frac{1}{4})}^{3 x} = 4^{- 3 x} = {{(4^{3})}^{\frac{1}{3}}}^{- 3 x} = 64^{- 3 x}

\Rightarrow 4 x = - 3 x \Rightarrow 12 x = 0 \Rightarrow x = 0