Question-180190

Question Number 180190 by Ar Brandon last updated on 08/Nov/22

Answered by Acem last updated on 09/Nov/22

X (Ω) = {5, 2, 1, 0}; P (X = 0) = 0.4

x_{i} 5 2 1 0

P (X = x_{i}) 0.1 0.2 0.3 0.4

V (x) = \underset{i = 1}{\sum^{n}} x_{i}^{2} p_{i} - {[E (x)]}^{2} \dots (1)

E (x) = \underset{i = 1}{\sum^{n}} x_{i} p_{i} = 1.2

V (x) = 3.6 - 1.44 = 2.16

Commented by Ar Brandon last updated on 09/Nov/22

Thank you, Sir!