Question Number 180254 by Noorzai last updated on 09/Nov/22
Answered by mr W last updated on 09/Nov/22
$$\left(\mathrm{2}−\sqrt{\mathrm{3}}\right)^{\mathrm{cos}\:{x}} =\left(\frac{\mathrm{1}}{\mathrm{2}−\sqrt{\mathrm{3}}}\right)^{\mathrm{sin}\:{x}} =\left(\mathrm{2}−\sqrt{\mathrm{3}}\right)^{−\mathrm{sin}\:{x}} \\ $$$$\Rightarrow\mathrm{cos}\:{x}=−\mathrm{sin}\:{x} \\ $$$$\Rightarrow\mathrm{cot}\:{x}=−\mathrm{1} \\ $$