Menu Close

Question-18046




Question Number 18046 by virus last updated on 14/Jul/17
Answered by mrW1 last updated on 14/Jul/17
t_(P−D) =10/2=5 s  t_(P−B) =6/2=3 s  h=h_(P−D) −h_(P−N) =(1/2)g(5^2 −3^2 )=80 m
$$\mathrm{t}_{\mathrm{P}−\mathrm{D}} =\mathrm{10}/\mathrm{2}=\mathrm{5}\:\mathrm{s} \\ $$$$\mathrm{t}_{\mathrm{P}−\mathrm{B}} =\mathrm{6}/\mathrm{2}=\mathrm{3}\:\mathrm{s} \\ $$$$\mathrm{h}=\mathrm{h}_{\mathrm{P}−\mathrm{D}} −\mathrm{h}_{\mathrm{P}−\mathrm{N}} =\frac{\mathrm{1}}{\mathrm{2}}\mathrm{g}\left(\mathrm{5}^{\mathrm{2}} −\mathrm{3}^{\mathrm{2}} \right)=\mathrm{80}\:\mathrm{m} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *