Question Number 180576 by Acem last updated on 14/Nov/22
Commented by Acem last updated on 14/Nov/22
$${a}\bullet\:{What}'{s}\:{the}\:{probability}\:{that}\:{Rosy}\:{would}\:{stand} \\ $$$$\:{on}\:{the}\:{far}\:{left}\:{and}\:{Nathalie}\:{on}\:{the}\:{far}\:{right}? \\ $$$${b}\bullet\:{Same}\:{question}\:{but}\:{and}\:{you}\:{stand}\:{in}\:{the}\:{middle} \\ $$$$\:{in}\:{case}\:{you}\:{were}\:\mathrm{11}\:{person}? \\ $$$${c}\bullet\:{Same}\:{question}\:'{a}'\:{but}\:{or}\:{you}\:{stand}\:{on}\:{the}\:\mathrm{2}{nd} \\ $$$$\:{place}\:{on}\:{the}\:{right}\:{in}\:{case}\:{you}\:{were}\:\mathrm{11}\:{too}? \\ $$$${d}\bullet\:{What}'{s}\:{the}\:{probability}\:{that}\:{they}\:{stand}\:{look}\:{like} \\ $$$$\:{the}\:{picture}\:{above}? \\ $$$$ \\ $$
Answered by mr W last updated on 14/Nov/22
$$\left.{a}\right) \\ $$$${p}=\frac{\mathrm{5}!}{\mathrm{7}!}=\frac{\mathrm{1}}{\mathrm{42}} \\ $$
Commented by Acem last updated on 14/Nov/22
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Answered by mr W last updated on 14/Nov/22
$$\left.{b}\right) \\ $$$${p}=\frac{\mathrm{10}!}{\mathrm{11}!}=\frac{\mathrm{1}}{\mathrm{11}} \\ $$
Commented by Acem last updated on 14/Nov/22
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Commented by Acem last updated on 14/Nov/22
$${Sir},\:{same}\:{question}\:'{a}'\:,\:{Rosy},\:{Nathalie}\:{and}\:{you} \\ $$
Commented by mr W last updated on 14/Nov/22
$${then} \\ $$$${p}=\frac{\mathrm{8}!}{\mathrm{11}!}=\frac{\mathrm{1}}{\mathrm{990}} \\ $$
Answered by mr W last updated on 14/Nov/22
$$\left.{c}\right) \\ $$$${p}=\frac{\mathrm{8}!}{\mathrm{11}!}=\frac{\mathrm{1}}{\mathrm{990}} \\ $$
Commented by Acem last updated on 14/Nov/22
$${Same}\:{note}\:{above}\:{but}\:{Or}\:{you} \\ $$
Commented by mr W last updated on 14/Nov/22
$${then}\:{please}\:{make}\:{your}\:{question}\:{clear}\: \\ $$$${enough}.\:“{but}\:{and}\:{you}'',\:“{but}\:{or}\:{you}'', \\ $$$${what}\:{do}\:{you}\:{mean}\:{exactly}? \\ $$
Commented by Acem last updated on 14/Nov/22
$${Hello}\:{friend}, \\ $$$${b}\bullet\:{Same}\:'{a}'\:,\:{in}\:{case}\:{you}\:{were}\:\mathrm{11}: \\ $$$$\:{I}\:{meant}\:{that}\:{Rosy}\:{would}\:{stand}\:{on}\:{the}\:{far}\:{left} \\ $$$$\:{and}\:{Nathalie}\:{on}\:{the}\:{far}\:{right}\:{and}\:{you}\:{stand}\:{in} \\ $$$$\:{the}\:{middle}\:{in}\:{case}\:{you}\:{were}\:\mathrm{11}\:{person}? \\ $$$$ \\ $$$${c}\bullet\:{Rosy}\:{would}\:{stand}\:{on}\:{the}\:{far}\:{left}\:{and}\:{Nathalie} \\ $$$$\:{on}\:{the}\:{far}\:{right}\:{or}\:{you}\:{stand}\:{in}\:{the}\:\mathrm{2}{nd}\:{place} \\ $$$$\:{on}\:{the}\:{right}\:{in}\:{case}\:{you}\:{were}\:\mathrm{11}\:{person}? \\ $$$$ \\ $$
Answered by mr W last updated on 14/Nov/22
$$\left.{d}\right) \\ $$$${p}=\frac{\mathrm{1}}{\mathrm{7}!}=\frac{\mathrm{1}}{\mathrm{5040}} \\ $$
Commented by Acem last updated on 14/Nov/22
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