Question-180917

Question Number 180917 by anne1344 last updated on 19/Nov/22

Answered by mr W last updated on 19/Nov/22

c)

h_{m a x} = \frac{{(v \sin θ)}^{2}}{2 g} = \frac{{(15 \times \sin 20 °)}^{2}}{2 \times 9.81} = 1.34 m

d)

t = \frac{v \sin θ}{g} = \frac{15 \times \sin 20 °}{9.81} = 0.52 s

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