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Question-181151




Question Number 181151 by mr W last updated on 22/Nov/22
Answered by SEKRET last updated on 22/Nov/22
 (√2)
$$\:\sqrt{\mathrm{2}} \\ $$
Answered by SEKRET last updated on 22/Nov/22
$$ \\ $$
Commented by Rasheed.Sindhi last updated on 22/Nov/22
Advanced booking for answer?
$${Advanced}\:{booking}\:{for}\:{answer}? \\ $$
Commented by Acem last updated on 22/Nov/22
 @Rasheed, You made me laugh
$$\:@{Rasheed},\:{You}\:{made}\:{me}\:{laugh} \\ $$
Commented by Rasheed.Sindhi last updated on 23/Nov/22
Good morning Acem sir!
Answered by Acem last updated on 22/Nov/22
Commented by mr W last updated on 22/Nov/22
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Commented by Acem last updated on 22/Nov/22
 ; m= ℓ cos β
$$\:;\:{m}=\:\ell\:\mathrm{cos}\:\beta \\ $$
Answered by mr W last updated on 22/Nov/22
Commented by Acem last updated on 22/Nov/22
I liked this question!
$${I}\:{liked}\:{this}\:{question}! \\ $$
Commented by mr W last updated on 22/Nov/22
3^2 +(3+y)^2 =5^2   ⇒y=1  x^2 =1^2 +(5−1−3)^2 =2  ⇒x=(√2)
$$\mathrm{3}^{\mathrm{2}} +\left(\mathrm{3}+{y}\right)^{\mathrm{2}} =\mathrm{5}^{\mathrm{2}} \\ $$$$\Rightarrow{y}=\mathrm{1} \\ $$$${x}^{\mathrm{2}} =\mathrm{1}^{\mathrm{2}} +\left(\mathrm{5}−\mathrm{1}−\mathrm{3}\right)^{\mathrm{2}} =\mathrm{2} \\ $$$$\Rightarrow{x}=\sqrt{\mathrm{2}} \\ $$

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