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Question-181673




Question Number 181673 by cherokeesay last updated on 28/Nov/22
Answered by HeferH last updated on 28/Nov/22
A = (((r_1  + r_2 )BD)/2)    BD = 5 − (((16)/5) + 1) = ((25 − 21)/5) = (4/5)   A = (1/2)(2 + ((12)/5))(4/5)  = ((44)/(25)) u^2
A=(r1+r2)BD2BD=5(165+1)=25215=45A=12(2+125)45=4425u2
Commented by cherokeesay last updated on 29/Nov/22
Nice solution,  thank you sir.
Nicesolution,thankyousir.
Answered by a.lgnaoui last updated on 29/Nov/22
Area=1,76
Area=1,76
Answered by a.lgnaoui last updated on 29/Nov/22
Answered by a.lgnaoui last updated on 29/Nov/22
tan α=(3/4)    α=36,87  AE^2 =2^2 +4^2     AE=2(√5) ⇒DE=4  EF=(√(CE^2 +CF^2 )) =(√(16+9)) =5  sin α=((CF)/(EF))=(3/5)  =((BC)/(CE))  BC=((12)/5)=2,4  BE^2 =CE^2 −BC^2   ⇒ BE=3,2  alors   BD=DE−BE=0,8  par consequant:   Aire=A_1 +A_2   A_1 =(1/2)(AD×BD)=((2×0,8)/2)=0,8  A_2 =(1/2)(BD×BC)=((2,4×0,8)/2)=0,96  A=1,76
tanα=34α=36,87AE2=22+42AE=25DE=4EF=CE2+CF2=16+9=5sinα=CFEF=35=BCCEBC=125=2,4BE2=CE2BC2BE=3,2alorsBD=DEBE=0,8parconsequant:Aire=A1+A2A1=12(AD×BD)=2×0,82=0,8A2=12(BD×BC)=2,4×0,82=0,96A=1,76
Commented by cherokeesay last updated on 29/Nov/22
Nice !  thank you so much.
Nice!thankyousomuch.

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