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Question-181766




Question Number 181766 by HeferH last updated on 30/Nov/22
Answered by som(math1967) last updated on 30/Nov/22
 let radius of inner circle =r   ((CI)/r)=cosec20⇒CI=rcosec20   c=rcot30+rcot40  =r(((cos30sin40+cos40sin30)/(sin30sin40)))  =r(((2sin70)/(2sin20cos20)))  =r[((cos(90−70))/(sin20cos20))]=rcosec20=CI  ∴CI=c (proved)
letradiusofinnercircle=rCIr=cosec20CI=rcosec20c=rcot30+rcot40=r(cos30sin40+cos40sin30sin30sin40)=r(2sin702sin20cos20)=r[cos(9070)sin20cos20]=rcosec20=CICI=c(proved)

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