Menu Close

Question-182456




Question Number 182456 by yaslm last updated on 09/Dec/22
Commented by mr W last updated on 09/Dec/22
F=((π×5^2 )/2)×(6−((4×5)/(3π)))×62.4 lbf
$${F}=\frac{\pi×\mathrm{5}^{\mathrm{2}} }{\mathrm{2}}×\left(\mathrm{6}−\frac{\mathrm{4}×\mathrm{5}}{\mathrm{3}\pi}\right)×\mathrm{62}.\mathrm{4}\:{lbf} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *