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Question-182904




Question Number 182904 by mathlove last updated on 16/Dec/22
Answered by balliu last updated on 16/Dec/22
(√3)(cosx+sinx)−(cosx−sinx)=(√2)  ((√3)−1)cosx+((√3)+1)sinx=(√2)
$$\sqrt{\mathrm{3}}\left({cosx}+{sinx}\right)−\left({cosx}−{sinx}\right)=\sqrt{\mathrm{2}} \\ $$$$\left(\sqrt{\mathrm{3}}−\mathrm{1}\right){cosx}+\left(\sqrt{\mathrm{3}}+\mathrm{1}\right){sinx}=\sqrt{\mathrm{2}} \\ $$$$ \\ $$

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