Question Number 182995 by universe last updated on 18/Dec/22
Answered by som(math1967) last updated on 18/Dec/22
Commented by som(math1967) last updated on 18/Dec/22
$$\:{Area}=\mathrm{4}×\left\{\int_{\mathrm{0}} ^{\mathrm{1}} \sqrt{\mathrm{1}−{x}^{\mathrm{2}} }{dx}−\int_{\mathrm{0}} ^{\mathrm{1}} \left(\mathrm{1}−{x}\right){dx}\right. \\ $$$$=\mathrm{4}×\left\{\frac{\pi}{\mathrm{4}}−\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}}\right)\right\} \\ $$$$=\left(\pi−\mathrm{2}\right){squnit}\: \\ $$$$\:\left({d}\right) \\ $$
Commented by universe last updated on 18/Dec/22
$${thanks}\:{sir} \\ $$