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Question-183325




Question Number 183325 by Acem last updated on 25/Dec/22
Commented by Acem last updated on 25/Dec/22
 The polygon is a sqware
$$\:{The}\:{polygon}\:{is}\:{a}\:{sqware} \\ $$
Answered by Acem last updated on 27/Dec/22
Commented by Acem last updated on 27/Dec/22
             BC is a tangent of the circle, also BA   Also DC and from D there′s the 2nd tangent of   that circle “DE ” that means that the both triangles   △ CDF, △ EDF are congruents.
$$\:\:\:\:\:\:\:\:\:\:\:\:\:{BC}\:{is}\:{a}\:{tangent}\:{of}\:{the}\:{circle},\:{also}\:{BA} \\ $$$$\:\boldsymbol{{Also}}\:\boldsymbol{{DC}}\:{and}\:{from}\:{D}\:{there}'{s}\:{the}\:\mathrm{2}{nd}\:{tangent}\:{of} \\ $$$$\:{that}\:{circle}\:“{DE}\:''\:{that}\:{means}\:{that}\:{the}\:{both}\:{triangles} \\ $$$$\:\bigtriangleup\:{CDF},\:\bigtriangleup\:{EDF}\:{are}\:{congruents}. \\ $$

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