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Question-183500




Question Number 183500 by aurpeyz last updated on 26/Dec/22
Answered by mr W last updated on 26/Dec/22
Commented by mr W last updated on 26/Dec/22
max. N_x =30 KN
$${max}.\:{N}_{{x}} =\mathrm{30}\:{KN} \\ $$
Commented by aurpeyz last updated on 26/Dec/22
Thank you very much. I am very glad.   Although i will appreciate a little   explanation.
$${Thank}\:{you}\:{very}\:{much}.\:{I}\:{am}\:{very}\:{glad}.\: \\ $$$${Although}\:{i}\:{will}\:{appreciate}\:{a}\:{little}\: \\ $$$${explanation}. \\ $$
Commented by mr W last updated on 26/Dec/22
in CD:   no external force, ⇒F_x =0  in BC:  F_x =3P=30 KN  in AB:  F_x =3P−P=2P=20 KN
$${in}\:{CD}:\: \\ $$$${no}\:{external}\:{force},\:\Rightarrow{F}_{{x}} =\mathrm{0} \\ $$$${in}\:{BC}: \\ $$$${F}_{{x}} =\mathrm{3}{P}=\mathrm{30}\:{KN} \\ $$$${in}\:{AB}: \\ $$$${F}_{{x}} =\mathrm{3}{P}−{P}=\mathrm{2}{P}=\mathrm{20}\:{KN} \\ $$
Commented by aurpeyz last updated on 27/Dec/22
thanks
$${thanks} \\ $$

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