Question Number 183893 by Sulaymon last updated on 31/Dec/22
Commented by pablo1234523 last updated on 31/Dec/22
$${also}\:{from}\:{the}\:{graph}\:{it}\:{seems}\:{like}\:{a}>{b} \\ $$$${but}\:{none}\:{of}\:{the}\:{option}\:{satisfies}\:{it} \\ $$
Commented by mr W last updated on 31/Dec/22
$${please}\:{translate}\:{the}\:{question}\:{into} \\ $$$${english}! \\ $$$$ \\ $$$${i}\:{guess}\:{the}\:{question}\:{is}\:{which}\:{of}\:{the} \\ $$$${equations}\:{of}\:{the}\:{circle}\:{is}\:{correct}. \\ $$$$ \\ $$$${eqn}.\:{of}\:{circle}\:\left({x}−{a}\right)^{\mathrm{2}} +\left({y}−{b}\right)^{\mathrm{2}} ={r}^{\mathrm{2}} \\ $$$$ \\ $$$${from}\:{the}\:{graph}\:{we}\:{see}\:{that}\:{following}\: \\ $$$${conditions}\:{must}\:{be}\:{fulfilled}: \\ $$$$\left.\mathrm{1}\right)\:{a},{b}>\mathrm{0} \\ $$$$\left.\mathrm{2}\right)\:{a}<{r},\:{b}<{r}\:\Rightarrow{r}^{\mathrm{2}} >{a}^{\mathrm{2}} ,\:{r}^{\mathrm{2}} >{b}^{\mathrm{2}} \\ $$$$\left.\mathrm{3}\right)\:\sqrt{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }>{r}\:\Rightarrow{r}^{\mathrm{2}} <{a}^{\mathrm{2}} +{b}^{\mathrm{2}} \\ $$$$ \\ $$$$\left.{A}\left.\right)\left.,\:{B}\right),\:{C}\right){fulfill}\:{all}\:{three}\:{conditions} \\ $$$$\left.{and}\:{could}\:{be}\:{correct}.\:{D}\right)\:{is}\:{wrong}. \\ $$$$\left.{most}\:{likely}\:{is}\:{A}\right). \\ $$