Question Number 183974 by yaslm last updated on 01/Jan/23
Answered by MJS_new last updated on 01/Jan/23
$${x}={y}^{\mathrm{3}} +\mathrm{12}{y}+\mathrm{7} \\ $$$${y}^{\mathrm{3}} +\mathrm{12}{y}+\left(\mathrm{7}−{y}\right)=\mathrm{0} \\ $$$$\mathrm{use}\:\mathrm{Cardano}'\mathrm{s}\:\mathrm{Formula}\:\mathrm{to}\:\mathrm{get} \\ $$$${y}=\sqrt[{\mathrm{3}}]{\frac{{x}−\mathrm{7}}{\mathrm{2}}−\frac{\sqrt{{x}^{\mathrm{2}} −\mathrm{14}{x}+\mathrm{305}}}{\mathrm{2}}}+\sqrt[{\mathrm{3}}]{\frac{{x}−\mathrm{7}}{\mathrm{2}}+\frac{\sqrt{{x}^{\mathrm{2}} −\mathrm{14}{x}+\mathrm{305}}}{\mathrm{2}}} \\ $$