Menu Close

Question-184487




Question Number 184487 by Noorzai last updated on 07/Jan/23
Commented by Frix last updated on 07/Jan/23
=∫(((3/2))^(sin x) +((2/3))^(sin x) −2)dx  =2∫(cosh (ln (3/2) ×sin x) −1)dx  I don′t think we can solve this
$$=\int\left(\left(\frac{\mathrm{3}}{\mathrm{2}}\right)^{\mathrm{sin}\:{x}} +\left(\frac{\mathrm{2}}{\mathrm{3}}\right)^{\mathrm{sin}\:{x}} −\mathrm{2}\right){dx} \\ $$$$=\mathrm{2}\int\left(\mathrm{cosh}\:\left(\mathrm{ln}\:\frac{\mathrm{3}}{\mathrm{2}}\:×\mathrm{sin}\:{x}\right)\:−\mathrm{1}\right){dx} \\ $$$$\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{think}\:\mathrm{we}\:\mathrm{can}\:\mathrm{solve}\:\mathrm{this} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *