Question-184497

Question Number 184497 by Noorzai last updated on 07/Jan/23

Answered by SEKRET last updated on 07/Jan/23

x^{x^{x^{\dots .}}} = y x^{y} = y

x = y^{\frac{1}{y}} dx = - y^{\frac{1}{y} - 2} \cdot (\ln (y) - 1) dy

\int y \cdot (- 1) \cdot y^{\frac{1}{y} - 2} (lny - 1) dy =

- 1 \cdot \int y^{\frac{1}{y} - 1} \cdot (\ln (y) - 1) dy =

= \int y^{\frac{1}{y} - 1} dy - \int y^{\frac{1}{y} - 1} \cdot \ln (y) dy

\dots \dots

Facebook Tweet Pin