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Question-184503




Question Number 184503 by mr W last updated on 07/Jan/23
Answered by SEKRET last updated on 07/Jan/23
  a =(√(11+a))     a^2 = 11 + a     a^3 = 11a+a^2 =11a+11+a=12a+11     a^4 =12a^2 +11a=12∙11+12a+11a=12∙11+23a   a^4 −a^3 −11a^2 +11=   12∙11+23a−12a−11−11^2 −11a+11=  = 12∙11−11^2 +23a−23a=   = 11(12−11)=1∙11=11
a=11+aa2=11+aa3=11a+a2=11a+11+a=12a+11a4=12a2+11a=1211+12a+11a=1211+23aa4a311a2+11=1211+23a12a1111211a+11==1211112+23a23a==11(1211)=111=11
Commented by SEKRET last updated on 07/Jan/23
   a=(√(11+(√(11+(√(11+(√(11+(√(11+(√(11+(√(11+11+(√(11+....))))))))))))))))
a=11+11+11+11+11+11+11+11+11+.
Commented by mr W last updated on 07/Jan/23
a^2 −a=11  a^4 −a^3 −11a^2 +11  =a^2 (a^2 −a)−11a^2 +11  =11a^2 −11a^2 +11  =11
a2a=11a4a311a2+11=a2(a2a)11a2+11=11a211a2+11=11

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