Question-184503 Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 184503 by mr W last updated on 07/Jan/23 Answered by SEKRET last updated on 07/Jan/23 a=11+aa2=11+aa3=11a+a2=11a+11+a=12a+11a4=12a2+11a=12⋅11+12a+11a=12⋅11+23aa4−a3−11a2+11=12⋅11+23a−12a−11−112−11a+11==12⋅11−112+23a−23a==11(12−11)=1⋅11=11 Commented by SEKRET last updated on 07/Jan/23 a=11+11+11+11+11+11+11+11+11+…. Commented by mr W last updated on 07/Jan/23 a2−a=11a4−a3−11a2+11=a2(a2−a)−11a2+11=11a2−11a2+11=11 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: x-dy-y-x-2-y-2-dx-y-3-1-Next Next post: lim-x-x-x-x-1-x-2-4-1-3-4-6-3-5-2-1-2-3-4-3-4-5-6-5-6-7-pi-2-lim-x-x-x-x-1-x-2-1-4-3-4-3-6-5-1-e-pi-2-1-e Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.