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Question-18492




Question Number 18492 by virus last updated on 22/Jul/17
Commented by mrW1 last updated on 23/Jul/17
the force in k above block A is 3mg.  when the spring above A is cut, this  force is released, a force of 3mg is  acting on block A, therefore a_A =3g.    block B and C are still in equilibrium,  therefore a_B =a_C =0.
$$\mathrm{the}\:\mathrm{force}\:\mathrm{in}\:\mathrm{k}\:\mathrm{above}\:\mathrm{block}\:\mathrm{A}\:\mathrm{is}\:\mathrm{3mg}. \\ $$$$\mathrm{when}\:\mathrm{the}\:\mathrm{spring}\:\mathrm{above}\:\mathrm{A}\:\mathrm{is}\:\mathrm{cut},\:\mathrm{this} \\ $$$$\mathrm{force}\:\mathrm{is}\:\mathrm{released},\:\mathrm{a}\:\mathrm{force}\:\mathrm{of}\:\mathrm{3mg}\:\mathrm{is} \\ $$$$\mathrm{acting}\:\mathrm{on}\:\mathrm{block}\:\mathrm{A},\:\mathrm{therefore}\:\mathrm{a}_{\mathrm{A}} =\mathrm{3g}. \\ $$$$ \\ $$$$\mathrm{block}\:\mathrm{B}\:\mathrm{and}\:\mathrm{C}\:\mathrm{are}\:\mathrm{still}\:\mathrm{in}\:\mathrm{equilibrium}, \\ $$$$\mathrm{therefore}\:\mathrm{a}_{\mathrm{B}} =\mathrm{a}_{\mathrm{C}} =\mathrm{0}. \\ $$
Answered by mrW1 last updated on 23/Jul/17
a_B =a_C =0  a_A =3g
$$\mathrm{a}_{\mathrm{B}} =\mathrm{a}_{\mathrm{C}} =\mathrm{0} \\ $$$$\mathrm{a}_{\mathrm{A}} =\mathrm{3g} \\ $$

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