Question Number 185116 by Noorzai last updated on 17/Jan/23
Answered by MJS_new last updated on 17/Jan/23
$$\mathrm{6}^{{x}/\mathrm{2}} +\mathrm{2}^{{x}/\mathrm{2}} =\mathrm{4}^{{x}} \\ $$$$\mathrm{2}^{{x}/\mathrm{2}} \left(\mathrm{3}^{{x}/\mathrm{2}} +\mathrm{1}\right)=\mathrm{2}^{\mathrm{2}{x}} \\ $$$$\mathrm{3}^{{x}/\mathrm{2}} +\mathrm{1}=\mathrm{2}^{\mathrm{3}{x}/\mathrm{2}} \\ $$$$\mathrm{we}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate} \\ $$$${x}\approx.\mathrm{949990265861} \\ $$