Question Number 185420 by Ml last updated on 21/Jan/23
Commented by Frix last updated on 21/Jan/23
$$\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{think}\:\mathrm{this}\:\mathrm{can}\:\mathrm{be}\:\mathrm{simplified}. \\ $$
Answered by malwan last updated on 24/Jan/23
$$\left(\:^{\mathrm{3}} \sqrt{\mathrm{4}−\:^{\mathrm{3}} \sqrt{\mathrm{2}}}\right)\left(^{\mathrm{3}} \sqrt{\mathrm{2}^{\mathrm{2}} }+\:^{\mathrm{3}} \sqrt{\mathrm{2}}\:+\:\mathrm{1}\right) \\ $$