Question Number 185553 by Noorzai last updated on 23/Jan/23
Answered by Frix last updated on 23/Jan/23
$$\mathrm{3}{a}−\mathrm{5}{b}=\mathrm{0}\:\Rightarrow\:{b}=\frac{\mathrm{3}{a}}{\mathrm{5}} \\ $$$$\mathrm{2}{b}−\mathrm{3}{c}=\mathrm{0}\:\Rightarrow\:{c}=\frac{\mathrm{2}{b}}{\mathrm{3}}=\frac{\mathrm{2}{a}}{\mathrm{5}} \\ $$$$\frac{\mathrm{2}{a}−\frac{\mathrm{12}{a}}{\mathrm{5}}+\mathrm{2}{a}}{\frac{\mathrm{3}{a}}{\mathrm{5}}−\frac{\mathrm{6}{a}}{\mathrm{5}}}=−\frac{\mathrm{8}}{\mathrm{3}} \\ $$