Question Number 185781 by Mingma last updated on 27/Jan/23
Answered by ajfour last updated on 27/Jan/23
$${let}\:{BE}=\mathrm{4}{p}\:,\:\:{BD}=\mathrm{4}{q} \\ $$$${F}\left(\mathrm{3}{p},{q}\right)\:\:;\:\:\:{G}\left(\mathrm{3}{p}+\frac{\mathrm{3}}{\mathrm{4}},\:{q}+\mathrm{1}\right) \\ $$$${FG}=\sqrt{\frac{\mathrm{9}}{\mathrm{16}}+\mathrm{1}}=\frac{\mathrm{5}}{\mathrm{4}} \\ $$