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Question-185864




Question Number 185864 by Mingma last updated on 29/Jan/23
Answered by mr W last updated on 29/Jan/23
Commented by mr W last updated on 29/Jan/23
(a/b)=((s+t)/s)=1+(t/s)=1+(y/x)  ((b+c)/a)=((x+y)/x)=1+(y/x)=(a/b)  ⇒a^2 =b(b+c)  ⇒a^2 −b^2 =bc ✓
$$\frac{{a}}{{b}}=\frac{{s}+{t}}{{s}}=\mathrm{1}+\frac{{t}}{{s}}=\mathrm{1}+\frac{{y}}{{x}} \\ $$$$\frac{{b}+{c}}{{a}}=\frac{{x}+{y}}{{x}}=\mathrm{1}+\frac{{y}}{{x}}=\frac{{a}}{{b}} \\ $$$$\Rightarrow{a}^{\mathrm{2}} ={b}\left({b}+{c}\right) \\ $$$$\Rightarrow{a}^{\mathrm{2}} −{b}^{\mathrm{2}} ={bc}\:\checkmark \\ $$

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