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Question-185938




Question Number 185938 by Mingma last updated on 30/Jan/23
Answered by HeferH last updated on 30/Jan/23
Let S be the pink area and let 5k be the area   of ABC.   S(((3k)/2) + S) = (k − S)(((3k)/2)−S)   S  = ((3k)/8)   ((Pink)/(Area of ABC)) = (((3k)/8)/(5k)) = (3/(40))
LetSbethepinkareaandlet5kbetheareaofABC.S(3k2+S)=(kS)(3k2S)S=3k8PinkAreaofABC=3k85k=340
Commented by HeferH last updated on 30/Jan/23
Answered by mr W last updated on 30/Jan/23
Commented by mr W last updated on 30/Jan/23
DF=(3/5)×DC=(3/5)×BD  GE=(3/5)×BG=(3/8)×BE  [GDE]=(3/8)×[BED]                =(3/8)×(1/2)×[BEC]                =(3/8)×(1/2)×(2/5)×[ABC]                =(3/(40))×[ABC] ✓
DF=35×DC=35×BDGE=35×BG=38×BE[GDE]=38×[BED]=38×12×[BEC]=38×12×25×[ABC]=340×[ABC]

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