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Question-186376




Question Number 186376 by Rupesh123 last updated on 04/Feb/23
Answered by HeferH last updated on 04/Feb/23
Commented by HeferH last updated on 04/Feb/23
1.move triangle ADB
1.movetriangleADB
Commented by HeferH last updated on 04/Feb/23
Commented by HeferH last updated on 04/Feb/23
2. now ADH is isosceles, and also AHC is  isosceles (10°, 10°, 160°)
2.nowADHisisosceles,andalsoAHCisisosceles(10°,10°,160°)
Commented by HeferH last updated on 04/Feb/23
Commented by HeferH last updated on 04/Feb/23
3. △ ABH ≅ △ DCB
3.ABHDCB
Commented by HeferH last updated on 04/Feb/23
Commented by HeferH last updated on 04/Feb/23
4. now we want to find ∠ABH = ∠ BCD = x
4.nowwewanttofindABH=BCD=x
Commented by HeferH last updated on 04/Feb/23
Commented by HeferH last updated on 04/Feb/23
5. Since ∠BAD = 2∠ABD we can draw    this segment
5.SinceBAD=2ABDwecandrawthissegment
Commented by HeferH last updated on 04/Feb/23
Commented by HeferH last updated on 04/Feb/23
6. we have an equilateral triangle that    leads to another isosceles triangle   (100°, 40°,40°)
6.wehaveanequilateraltrianglethatleadstoanotherisoscelestriangle(100°,40°,40°)
Commented by HeferH last updated on 04/Feb/23
Commented by HeferH last updated on 04/Feb/23
7. finally ∠ABH = 40° = x
7.finallyABH=40°=x
Commented by HeferH last updated on 04/Feb/23
:∣
:∣

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