Question-186489

Question Number 186489 by Mingma last updated on 05/Feb/23

Answered by Frix last updated on 06/Feb/23

a^{2} + b^{2} + c^{2} = 1981^{2} = 7^{2} \times 283^{2}

2^{2} + 3^{2} + 6^{2} = 7^{2}

{(2 \times 283)}^{2} + {(3 \times 283)}^{2} + {(6 \times 283)}^{2} = {(7 \times 283)}^{2}

566^{2} + 849^{2} + 1698^{2} = 1981^{2}

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