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Question-186726




Question Number 186726 by Rupesh123 last updated on 09/Feb/23
Answered by cortano12 last updated on 09/Feb/23
f ′(x)=((3x^2 )/(1+ln x^3 ))=((3x^2 )/(ln ex^3 ))  f ′′(x)= ((6x.ln ex^3 −((3ex^2 )/(ex^3 )) .3x^2 )/((ln ex^3 )^2 ))
f(x)=3x21+lnx3=3x2lnex3f(x)=6x.lnex33ex2ex3.3x2(lnex3)2
Answered by Ar Brandon last updated on 09/Feb/23
(∂/∂t)∫_(u(t)) ^(v(t)) f(x, t)dx=∫_(u(t)) ^(v(t)) (∂/∂t)f(x, t)dx+[f(v(t), t)]v′(t)−[f(u(t), t)]u′(t)
tu(t)v(t)f(x,t)dx=u(t)v(t)tf(x,t)dx+[f(v(t),t)]v(t)[f(u(t),t)]u(t)

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